[Design with CSS 3793] Re: How to remove the white space at the top of the page?

Monday, September 30, 2013

0 comments

First, remove default margin from body and heading tags.


just add this bunch of code in your css file.

body,div,h1,h2,h3,h4,h5,h6,p{
margin: 0px;
padding: 0px;
}

On Sunday, July 14, 2013 8:10:09 PM UTC+5:30, justaguy wrote:

I'm stumbled by the following CSS issue,

How do we fix it?

Thanks.

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Re: get dropdown selected value and pass to another dropdown

Thursday, September 26, 2013

0 comments
MMZ,

Yes, you can use an IFRAME instead of AJAX.  That's actually how a lot of people built dynamic websites before AJAX was implemented.  They would send GET and POST requests through the IFRAME and the IFRAME would return JavaScript that would connect back into the original page and manipulate it. 

For current day examples, look up methods to transfer images .. we still have to use IFRAMES for that.  AJAX, at least to my knowledge, hasn't been updated to handle posting image data yet.

Now to your specific question ...

There are two ways to do that ...

#1 .. the HTML A tag <a href="somepage.php" target=""> has the property "target" in it.

This allows you to specify the IFRAME by "NAME".  While this example doesn't contain the year, you can use on onCLICK method to add the year before firing off the link.  And, it's being used to set up the next 2 examples .. note the property "TARGET"

#2 .. through JavaScript

window.frames [ target ].location = "somepage.php?yr=" + year + "&";

Note that option #2 will only execute a GET request.  Todo a POST request, you will need a FORM to call the IFRAME.  This example provides both HTML and JavaScript options for submitting the form.  I also included the file upload INPUT tag just for grins and giggles.

#3  through and IFRAME with a FORM

<form id="getReport" method="POST" action="somepage.php" target="getReportFrame">
<input id="reportYear" type="hidden" name="reportYear" value="">
<input id="uploadReport" type="file" name="uploadReport" value="">
<input id="submit" type="submit" name="submit" value="submit">
</form>

<iframe name="getReportFrame">
</iframe>

<script>
function cmdGetReport (yr)
{
    $("#reportYear").val (yr);
    $("#getReport").submit();
}
</script>




On 9/25/2013 8:11 AM, MMZ wrote:
Thanks alot for your help. your answer is very complete and descriptive.
Just one more question, is it possible to get the year and report value and send them to an iframe of the same page because I want to keep the dorpdowns on the page.

Thanks again

On Tuesday, September 24, 2013 8:40:58 PM UTC-4, ENetArch wrote:
Hello MMZ,

If I understand what you want to do, you have 2 select statements on the same page.

The first select statement allows the user to select a year.  You want to pass that year back to the server and have PHP do something.  (what you want the server to do is unclear). 

The second select statement provides a list of URLs. (No examples were given, so I'm not sure how the Year value is used in the URLs).

OK, so ... here are some thoughts.

PHP only runs on the server, and it does not run inline as the page is drawn on the web browser.  Instead you have to think of the PHP and JavaScript in a client server fashion.  So, your user types in

Http://www.dirtysocks.com/
The server executes the index.php page
=====
<html>
...
<!-- generated options from PHP script -->
<?php
$result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
while ($row = mysql_fetch_assoc($result1))
{
      $period= $row['year'];
      $period_id=$row['id'];
      echo "<option  value=\"$period\">$period</option>";
}
?>
<!-- generated options from PHP script -->
...
</html>
=====

The server responds by sending only the HTML for the index.php page.
=====
<html>
...
<script scr="jQuery.js"></script>
<script scr="muddySocks.js"></script>
...
<body>
<form method="post">
        Report Period:
<select id="selectYear" onchange="muddySocks.cmdSelectedYear();">
            <option> Select An Option </option>
<!-- generated options from PHP script -->
            <option value="1973"> 1973 </option>
            <option value="1973"> 1986 </option>
            <option value="1973"> 1995 </option>
            <option value="1973"> 2000 </option>
            <option value="1973"> 2008 </option>
<!-- generated options from PHP script -->
</select>

<select id="selectReport" onchange="muddySocks.cmdSelectedReport();">
            <option> Select An Option </option>
<!-- generated options from AJAX call -->
<!-- generated options from AJAX call -->
</select>

...
</html>
=====

The user selects an option from the select statement, which in this case calls muddySocks.cmdSelectedYear ();

=====
// The JavaScript looks something like:
// Note: this library requires JQUERY ...

var muddySocks =
{
    selectedYear : "",

    cmdSelectedYear : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        muddySocks.selectedYear = value; // or text;

        // next I'll use JQUERY to call the web server for the Report List
        $.ajax (
            {
                url : "getYear.php?year=" + value + "&",
                method : "get",
                success : function (szHtml)
                {
                     if (szHtml.length >0)
                     { $("#selectReport").html (szHtml); }
                    else
                    { window.alert ("nothing returned"); }
                },
                error : function ()
                { window.alert ("ajax call failed"); },
            });
    },

    cmdSelectReport : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        window.location = "genReport.php?" +
            "year=" + muddysocks.selectedYear + "&"
            "report=" + value + "&";
    }
};
=====

Now "getYear.php" does a second query against the database, or something else to create a list of reports available for that year.

=====
<?
$szRtn = <<<HEREDOC
<option value="1">Report #1</option>
<option value="2">Report #2</option>
<option value="3">Report #3</option>
<option value="4">Report #4</option>
<option value="5">Report #5</option>
HEREDOC;

print ($szRtn);
?>
=====

Hope this helps you understand how your page might work a little better.

Mike,


On 9/24/2013 10:55 AM, MMZ wrote:
Hi,
I have two dropdown and want to get the selected year value of the first one and add it to the url of the header page and also to the second dropdown url options so that when I select a php page from the second dropdown I can see the year value on the page.I past my code here but the selected year doesn't show on the php page. 



<form method="post">
        Report Period:
        <select name="mySelect" id="mySelect" onchange="'header.php?year='+this.value" >
            <option style="display:none;"> Select</option>-->

            <?php
          
            $result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
            while ($row = mysql_fetch_assoc($result1)) {
            
                $period= $row['year'];
           
              $period_id=$row['id'];
           
                echo "<option  value=\"$period\">$period</option>";
              
            }
           
           
            ?>
       
        </select>
 Report Type:
        <select name="selectreport"  id="selectreport" > 

     
        <option style="display:none;">--Select--</option>
    
   
            <?php

           echo "<option value=\"".reportA.".php?org_id={$org_id}&year=".$_GET['year']."\">report A</option>";
            echo "<option value=\"" . reportB . ".php?org_id={$org_id}&year=".$_GET['year']."\">report B</option>";
        
            ?>

        </select>
        <input type=submit name=button method="post"  onClick="window.open(selectreport.value,
     'popUpWindow','height=800,width=1000,left=200,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');"value="view" >

    </form>
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MASTER PSYCHIC READER~ ACCURATE & AMUSING

Wednesday, September 25, 2013

0 comments
Your first 3 minutes are FREE talking live with me.

Please visit my
website at: http://www.keen.com/Ask+Fran

Or,
call me right now at: 1-800-275-5336 x0160

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Re: get dropdown selected value and pass to another dropdown

0 comments
Thanks alot for your help. your answer is very complete and descriptive.
Just one more question, is it possible to get the year and report value and send them to an iframe of the same page because I want to keep the dorpdowns on the page.

Thanks again

On Tuesday, September 24, 2013 8:40:58 PM UTC-4, ENetArch wrote:
Hello MMZ,

If I understand what you want to do, you have 2 select statements on the same page.

The first select statement allows the user to select a year.  You want to pass that year back to the server and have PHP do something.  (what you want the server to do is unclear). 

The second select statement provides a list of URLs. (No examples were given, so I'm not sure how the Year value is used in the URLs).

OK, so ... here are some thoughts.

PHP only runs on the server, and it does not run inline as the page is drawn on the web browser.  Instead you have to think of the PHP and JavaScript in a client server fashion.  So, your user types in

Http://www.dirtysocks.com/
The server executes the index.php page
=====
<html>
...
<!-- generated options from PHP script -->
<?php
$result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
while ($row = mysql_fetch_assoc($result1))
{
      $period= $row['year'];
      $period_id=$row['id'];
      echo "<option  value=\"$period\">$period</option>";
}
?>
<!-- generated options from PHP script -->
...
</html>
=====

The server responds by sending only the HTML for the index.php page.
=====
<html>
...
<script scr="jQuery.js"></script>
<script scr="muddySocks.js"></script>
...
<body>
<form method="post">
        Report Period:
<select id="selectYear" onchange="muddySocks.cmdSelectedYear();">
            <option> Select An Option </option>
<!-- generated options from PHP script -->
            <option value="1973"> 1973 </option>
            <option value="1973"> 1986 </option>
            <option value="1973"> 1995 </option>
            <option value="1973"> 2000 </option>
            <option value="1973"> 2008 </option>
<!-- generated options from PHP script -->
</select>

<select id="selectReport" onchange="muddySocks.cmdSelectedReport();">
            <option> Select An Option </option>
<!-- generated options from AJAX call -->
<!-- generated options from AJAX call -->
</select>

...
</html>
=====

The user selects an option from the select statement, which in this case calls muddySocks.cmdSelectedYear ();

=====
// The JavaScript looks something like:
// Note: this library requires JQUERY ...

var muddySocks =
{
    selectedYear : "",

    cmdSelectedYear : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        muddySocks.selectedYear = value; // or text;

        // next I'll use JQUERY to call the web server for the Report List
        $.ajax (
            {
                url : "getYear.php?year=" + value + "&",
                method : "get",
                success : function (szHtml)
                {
                     if (szHtml.length >0)
                     { $("#selectReport").html (szHtml); }
                    else
                    { window.alert ("nothing returned"); }
                },
                error : function ()
                { window.alert ("ajax call failed"); },
            });
    },

    cmdSelectReport : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        window.location = "genReport.php?" +
            "year=" + muddysocks.selectedYear + "&"
            "report=" + value + "&";
    }
};
=====

Now "getYear.php" does a second query against the database, or something else to create a list of reports available for that year.

=====
<?
$szRtn = <<<HEREDOC
<option value="1">Report #1</option>
<option value="2">Report #2</option>
<option value="3">Report #3</option>
<option value="4">Report #4</option>
<option value="5">Report #5</option>
HEREDOC;

print ($szRtn);
?>
=====

Hope this helps you understand how your page might work a little better.

Mike,


On 9/24/2013 10:55 AM, MMZ wrote:
Hi,
I have two dropdown and want to get the selected year value of the first one and add it to the url of the header page and also to the second dropdown url options so that when I select a php page from the second dropdown I can see the year value on the page.I past my code here but the selected year doesn't show on the php page. 



<form method="post">
        Report Period:
        <select name="mySelect" id="mySelect" onchange="'header.php?year='+this.value" >
            <option style="display:none;"> Select</option>-->

            <?php
          
            $result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
            while ($row = mysql_fetch_assoc($result1)) {
            
                $period= $row['year'];
           
              $period_id=$row['id'];
           
                echo "<option  value=\"$period\">$period</option>";
              
            }
           
           
            ?>
       
        </select>
 Report Type:
        <select name="selectreport"  id="selectreport" > 

     
        <option style="display:none;">--Select--</option>
    
   
            <?php

           echo "<option value=\"".reportA.".php?org_id={$org_id}&year=".$_GET['year']."\">report A</option>";
            echo "<option value=\"" . reportB . ".php?org_id={$org_id}&year=".$_GET['year']."\">report B</option>";
        
            ?>

        </select>
        <input type=submit name=button method="post"  onClick="window.open(selectreport.value,
     'popUpWindow','height=800,width=1000,left=200,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');"value="view" >

    </form>
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Re: get dropdown selected value and pass to another dropdown

Tuesday, September 24, 2013

0 comments
Hello MMZ,

If I understand what you want to do, you have 2 select statements on the same page.

The first select statement allows the user to select a year.  You want to pass that year back to the server and have PHP do something.  (what you want the server to do is unclear). 

The second select statement provides a list of URLs. (No examples were given, so I'm not sure how the Year value is used in the URLs).

OK, so ... here are some thoughts.

PHP only runs on the server, and it does not run inline as the page is drawn on the web browser.  Instead you have to think of the PHP and JavaScript in a client server fashion.  So, your user types in

Http://www.dirtysocks.com/
The server executes the index.php page
=====
<html>
...
<!-- generated options from PHP script -->
<?php
$result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
while ($row = mysql_fetch_assoc($result1))
{
      $period= $row['year'];
      $period_id=$row['id'];
      echo "<option  value=\"$period\">$period</option>";
}
?>
<!-- generated options from PHP script -->
...
</html>
=====

The server responds by sending only the HTML for the index.php page.
=====
<html>
...
<script scr="jQuery.js"></script>
<script scr="muddySocks.js"></script>
...
<body>
<form method="post">
        Report Period:
<select id="selectYear" onchange="muddySocks.cmdSelectedYear();">
            <option> Select An Option </option>
<!-- generated options from PHP script -->
            <option value="1973"> 1973 </option>
            <option value="1973"> 1986 </option>
            <option value="1973"> 1995 </option>
            <option value="1973"> 2000 </option>
            <option value="1973"> 2008 </option>
<!-- generated options from PHP script -->
</select>

<select id="selectReport" onchange="muddySocks.cmdSelectedReport();">
            <option> Select An Option </option>
<!-- generated options from AJAX call -->
<!-- generated options from AJAX call -->
</select>

...
</html>
=====

The user selects an option from the select statement, which in this case calls muddySocks.cmdSelectedYear ();

=====
// The JavaScript looks something like:
// Note: this library requires JQUERY ...

var muddySocks =
{
    selectedYear : "",

    cmdSelectedYear : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        muddySocks.selectedYear = value; // or text;

        // next I'll use JQUERY to call the web server for the Report List
        $.ajax (
            {
                url : "getYear.php?year=" + value + "&",
                method : "get",
                success : function (szHtml)
                {
                     if (szHtml.length >0)
                     { $("#selectReport").html (szHtml); }
                    else
                    { window.alert ("nothing returned"); }
                },
                error : function ()
                { window.alert ("ajax call failed"); },
            });
    },

    cmdSelectReport : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        window.location = "genReport.php?" +
            "year=" + muddysocks.selectedYear + "&"
            "report=" + value + "&";
    }
};
=====

Now "getYear.php" does a second query against the database, or something else to create a list of reports available for that year.

=====
<?
$szRtn = <<<HEREDOC
<option value="1">Report #1</option>
<option value="2">Report #2</option>
<option value="3">Report #3</option>
<option value="4">Report #4</option>
<option value="5">Report #5</option>
HEREDOC;

print ($szRtn);
?>
=====

Hope this helps you understand how your page might work a little better.

Mike,


On 9/24/2013 10:55 AM, MMZ wrote:
Hi,
I have two dropdown and want to get the selected year value of the first one and add it to the url of the header page and also to the second dropdown url options so that when I select a php page from the second dropdown I can see the year value on the page.I past my code here but the selected year doesn't show on the php page. 



<form method="post">
        Report Period:
        <select name="mySelect" id="mySelect" onchange="'header.php?year='+this.value" >
            <option style="display:none;"> Select</option>-->

            <?php
          
            $result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
            while ($row = mysql_fetch_assoc($result1)) {
            
                $period= $row['year'];
           
              $period_id=$row['id'];
           
                echo "<option  value=\"$period\">$period</option>";
              
            }
           
           
            ?>
       
        </select>
 Report Type:
        <select name="selectreport"  id="selectreport" > 

     
        <option style="display:none;">--Select--</option>
    
   
            <?php

           echo "<option value=\"".reportA.".php?org_id={$org_id}&year=".$_GET['year']."\">report A</option>";
            echo "<option value=\"" . reportB . ".php?org_id={$org_id}&year=".$_GET['year']."\">report B</option>";
        
            ?>

        </select>
        <input type=submit name=button method="post"  onClick="window.open(selectreport.value,
     'popUpWindow','height=800,width=1000,left=200,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');"value="view" >

    </form>
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get dropdown selected value and pass to another dropdown

0 comments
Hi,
I have two dropdown and want to get the selected year value of the first one and add it to the url of the header page and also to the second dropdown url options so that when I select a php page from the second dropdown I can see the year value on the page.I past my code here but the selected year doesn't show on the php page. 



<form method="post">
        Report Period:
        <select name="mySelect" id="mySelect" onchange="'header.php?year='+this.value" >
            <option style="display:none;"> Select</option>-->

            <?php
          
            $result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
            while ($row = mysql_fetch_assoc($result1)) {
            
                $period= $row['year'];
           
              $period_id=$row['id'];
           
                echo "<option  value=\"$period\">$period</option>";
              
            }
           
           
            ?>
       
        </select>
 Report Type:
        <select name="selectreport"  id="selectreport" > 

     
        <option style="display:none;">--Select--</option>
    
   
            <?php

           echo "<option value=\"".reportA.".php?org_id={$org_id}&year=".$_GET['year']."\">report A</option>";
            echo "<option value=\"" . reportB . ".php?org_id={$org_id}&year=".$_GET['year']."\">report B</option>";
        
            ?>

        </select>
        <input type=submit name=button method="post"  onClick="window.open(selectreport.value,
     'popUpWindow','height=800,width=1000,left=200,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');"value="view" >

    </form>

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last fashion

Friday, September 20, 2013

0 comments

 Women Bag

Brown crocodile bag

Daim bag

Brown bag

 

www.aswaq-tetouan.com

Woman Shoes

Women's leather shoes

Boots black leather

Shoes with platform

Brown crocodile shoes

Burgundy boots 

Boots caramel color

Crocodile brown boots

Brown crocodile shoes

Daim boots

Daim shoes

 

www.aswaq-tetouan.com

 

Perfumes and Makeup

Blush perfume

Cocolay Perfume

Feelings perfume

Ocean Blue perfume

Tycoon Perfume

Oriflame Perfume

Corp cream

Black Mascara 

Anti-Acne

 Flamboyant Perfumes

Brightening Powder

 

www.aswaq-tetouan.com

 

Modern clothes 

Haut plissé

Haut à manches courtes

Lot 3 débardeurs

Blouse avec manches tombantes

Lot 3 polos piqué manches courtes

salopit jeans

 

www.aswaq-tetouan.com

 

watches

for woman1

for women2

for women3

for men1

for men2

for men3

 

www.aswaq-tetouan.com

 

traditional clothes

 

3abaya chaymae 1

3abaya chaymae 2

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3abaya chaymae 5

3abaya chaymae 6

3abaya chaymae 7

 

www.aswaq-tetouan.com

 

 

Site Aswaq Tetouan ,the first electronic Market for Tetouan city sellers.

Publish all the new in the market of merchandise , prices  , offers and discounts.

Which we communicate with our customers  in all part of Morocco and the world to give yours the opportunity to shop from your home or through your phone

 

email : aswaqtetouan@gmail.com      

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Re: Loading javascripts to another.

Wednesday, September 18, 2013

0 comments
If that doesn't work, before trying to call the function check it's existence first by creating a check function.

function checkFunc() {
if (!functionName)
    setTimeout(checkFunc,50)
else
    functionName();



On 9/17/2013 9:52 AM, Israel wrote:
It sounds like the file isn't completely loading; calling a function that's in helper.js immediately after loading it will cause undefined error.

Try waiting for the window's load event to fire.

window.addEventListener("load", function(){
      helperFunctionName();
});

Or you can of course use <body onload="helperFunctionName();">

On Tuesday, September 17, 2013 6:20:04 AM UTC-4, smith john wrote:
What is the best way to load javascript to load another without errors. I loaded with dynamic loading and gives undefined error for running the loaded function after the files loaded. 

I put 
// CODE
var head= document.getElementsByTagName('head')[0];
   var script= document.createElement('script');
   script.type= 'text/javascript';
   script.src= 'helper.js';
   head.appendChild(script); 
//End CODE

then, run the loaded function and gives the function undefined error. The files are loaded and added to head section in chrome console. The reference said dynamic loading functions are relied on the browser.  I tried $.getScript() and DOM to add elements but it does not work.

Please tell me how to fix the errors. Or how to call function properly, for misplacement.
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Re: Loading javascripts to another.

Tuesday, September 17, 2013

0 comments

<html>
<head>
<title>Dynamic Script Loader</title>
<script id='script'></script>
<script>
function OnLoad() {
   
var script = document.getElementById("script");
    script
.src = "helper.js";
}
</script>
</head>
<body onload='OnLoad()'>
<div id='msg'></div>
</body>
</html>

helper.js ----------------------------------------------------------------------------
document.getElementById("msg").innerHTML = "Success!";

The above works in Chrome, IE, Firefox, Opera, and Safari. 

On Tuesday, September 17, 2013 6:20:04 AM UTC-4, smith john wrote:
What is the best way to load javascript to load another without errors. I loaded with dynamic loading and gives undefined error for running the loaded function after the files loaded. 

I put 
// CODE
var head= document.getElementsByTagName('head')[0];
   var script= document.createElement('script');
   script.type= 'text/javascript';
   script.src= 'helper.js';
   head.appendChild(script); 
//End CODE

then, run the loaded function and gives the function undefined error. The files are loaded and added to head section in chrome console. The reference said dynamic loading functions are relied on the browser.  I tried $.getScript() and DOM to add elements but it does not work.

Please tell me how to fix the errors. Or how to call function properly, for misplacement.

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To unsubscribe from this group and stop receiving emails from it, send an email to javascript-information+unsubscribe@googlegroups.com.
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Re: Loading javascripts to another.

0 comments
It sounds like the file isn't completely loading; calling a function that's in helper.js immediately after loading it will cause undefined error.

Try waiting for the window's load event to fire.

window.addEventListener("load", function(){
      helperFunctionName();
});

Or you can of course use <body onload="helperFunctionName();">

On Tuesday, September 17, 2013 6:20:04 AM UTC-4, smith john wrote:
What is the best way to load javascript to load another without errors. I loaded with dynamic loading and gives undefined error for running the loaded function after the files loaded. 

I put 
// CODE
var head= document.getElementsByTagName('head')[0];
   var script= document.createElement('script');
   script.type= 'text/javascript';
   script.src= 'helper.js';
   head.appendChild(script); 
//End CODE

then, run the loaded function and gives the function undefined error. The files are loaded and added to head section in chrome console. The reference said dynamic loading functions are relied on the browser.  I tried $.getScript() and DOM to add elements but it does not work.

Please tell me how to fix the errors. Or how to call function properly, for misplacement.

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You received this message because you are subscribed to the Google Groups "JavaScript Forum" group.
To unsubscribe from this group and stop receiving emails from it, send an email to javascript-information+unsubscribe@googlegroups.com.
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Loading javascripts to another.

0 comments
What is the best way to load javascript to load another without errors. I loaded with dynamic loading and gives undefined error for running the loaded function after the files loaded. 

I put 
// CODE
var head= document.getElementsByTagName('head')[0];
   var script= document.createElement('script');
   script.type= 'text/javascript';
   script.src= 'helper.js';
   head.appendChild(script); 
//End CODE

then, run the loaded function and gives the function undefined error. The files are loaded and added to head section in chrome console. The reference said dynamic loading functions are relied on the browser.  I tried $.getScript() and DOM to add elements but it does not work.

Please tell me how to fix the errors. Or how to call function properly, for misplacement.

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To unsubscribe from this group and stop receiving emails from it, send an email to javascript-information+unsubscribe@googlegroups.com.
For more options, visit https://groups.google.com/groups/opt_out.

Ice and Snow Photoshop Styles

0 comments
Hi Check out these ice and snow textures that you can use to add a realistic look to your text styles. http://www.psd-dude.com/tutorials/resources/ice-and-snow-photoshop-styles.aspx enjoy, John

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Modern Market

Saturday, September 14, 2013

0 comments

 

the shopping is a very important thing for people but

there is many people didn't know how to doing it fast.

there are some type to enjoy shopping and  save money and time:

by use the internet to buy some clothes like theses

 

Modern clothes 

Haut plissé

Haut à manches courtes

Lot 3 débardeurs

Blouse avec manches tombantes

Lot 3 polos piqué manches courtes

salopit jeans

 

www.aswaq-tetouan.com

 

watches

for woman1

for women2

for women3

for men1

for men2

for men3

 

www.aswaq-tetouan.com

 

traditional clothes

 

3abaya chaymae 1

3abaya chaymae 2

3abaya chaymae 3

3abaya chaymae 4

3abaya chaymae 5

3abaya chaymae 6

3abaya chaymae 7

 

www.aswaq-tetouan.com

 

 

 

Shoes

GUCCI shoes

DG shoes

italian shoes

urban shoes

tissu shoes

 

www.aswaq-tetouan.com

 

 Perfumes and Makeup

Corp cream

Black Mascara 

Anti-Acne

 Flamboyant Perfumes

Tycoon Perfumes

Brightening Powder

 

www.aswaq-tetouan.com

 

Site Aswaq Tetouan ,the first electronic Market for Tetouan city sellers.

Publish all the new in the market of merchandise , prices  , offers and discounts.

Which we communicate with our customers  in all part of Morocco and the world to give yours the opportunity to shop from your home or through your phone

 

email : aswaqtetouan@gmail.com     

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