Re: get dropdown selected value and pass to another dropdown

Tuesday, September 24, 2013

Hello MMZ,

If I understand what you want to do, you have 2 select statements on the same page.

The first select statement allows the user to select a year.  You want to pass that year back to the server and have PHP do something.  (what you want the server to do is unclear). 

The second select statement provides a list of URLs. (No examples were given, so I'm not sure how the Year value is used in the URLs).

OK, so ... here are some thoughts.

PHP only runs on the server, and it does not run inline as the page is drawn on the web browser.  Instead you have to think of the PHP and JavaScript in a client server fashion.  So, your user types in

Http://www.dirtysocks.com/
The server executes the index.php page
=====
<html>
...
<!-- generated options from PHP script -->
<?php
$result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
while ($row = mysql_fetch_assoc($result1))
{
      $period= $row['year'];
      $period_id=$row['id'];
      echo "<option  value=\"$period\">$period</option>";
}
?>
<!-- generated options from PHP script -->
...
</html>
=====

The server responds by sending only the HTML for the index.php page.
=====
<html>
...
<script scr="jQuery.js"></script>
<script scr="muddySocks.js"></script>
...
<body>
<form method="post">
        Report Period:
<select id="selectYear" onchange="muddySocks.cmdSelectedYear();">
            <option> Select An Option </option>
<!-- generated options from PHP script -->
            <option value="1973"> 1973 </option>
            <option value="1973"> 1986 </option>
            <option value="1973"> 1995 </option>
            <option value="1973"> 2000 </option>
            <option value="1973"> 2008 </option>
<!-- generated options from PHP script -->
</select>

<select id="selectReport" onchange="muddySocks.cmdSelectedReport();">
            <option> Select An Option </option>
<!-- generated options from AJAX call -->
<!-- generated options from AJAX call -->
</select>

...
</html>
=====

The user selects an option from the select statement, which in this case calls muddySocks.cmdSelectedYear ();

=====
// The JavaScript looks something like:
// Note: this library requires JQUERY ...

var muddySocks =
{
    selectedYear : "",

    cmdSelectedYear : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        muddySocks.selectedYear = value; // or text;

        // next I'll use JQUERY to call the web server for the Report List
        $.ajax (
            {
                url : "getYear.php?year=" + value + "&",
                method : "get",
                success : function (szHtml)
                {
                     if (szHtml.length >0)
                     { $("#selectReport").html (szHtml); }
                    else
                    { window.alert ("nothing returned"); }
                },
                error : function ()
                { window.alert ("ajax call failed"); },
            });
    },

    cmdSelectReport : function ()
    {
        var text = $(this).text();
        var value = $(this).val();
        alert("Selected text=" + text + " Selected value= " + value);

        window.location = "genReport.php?" +
            "year=" + muddysocks.selectedYear + "&"
            "report=" + value + "&";
    }
};
=====

Now "getYear.php" does a second query against the database, or something else to create a list of reports available for that year.

=====
<?
$szRtn = <<<HEREDOC
<option value="1">Report #1</option>
<option value="2">Report #2</option>
<option value="3">Report #3</option>
<option value="4">Report #4</option>
<option value="5">Report #5</option>
HEREDOC;

print ($szRtn);
?>
=====

Hope this helps you understand how your page might work a little better.

Mike,


On 9/24/2013 10:55 AM, MMZ wrote:
Hi,
I have two dropdown and want to get the selected year value of the first one and add it to the url of the header page and also to the second dropdown url options so that when I select a php page from the second dropdown I can see the year value on the page.I past my code here but the selected year doesn't show on the php page. 



<form method="post">
        Report Period:
        <select name="mySelect" id="mySelect" onchange="'header.php?year='+this.value" >
            <option style="display:none;"> Select</option>-->

            <?php
          
            $result1 = mysql_query("select id,year from year_data where org_id=$org_id") or die(mysql_error());
          
            while ($row = mysql_fetch_assoc($result1)) {
            
                $period= $row['year'];
           
              $period_id=$row['id'];
           
                echo "<option  value=\"$period\">$period</option>";
              
            }
           
           
            ?>
       
        </select>
 Report Type:
        <select name="selectreport"  id="selectreport" > 

     
        <option style="display:none;">--Select--</option>
    
   
            <?php

           echo "<option value=\"".reportA.".php?org_id={$org_id}&year=".$_GET['year']."\">report A</option>";
            echo "<option value=\"" . reportB . ".php?org_id={$org_id}&year=".$_GET['year']."\">report B</option>";
        
            ?>

        </select>
        <input type=submit name=button method="post"  onClick="window.open(selectreport.value,
     'popUpWindow','height=800,width=1000,left=200,top=100,resizable=yes,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no, status=yes');"value="view" >

    </form>
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