How about this as an alternative?
-- var MapInfo = {
center: new google.maps.LatLng(0,0),
zoom: 3,
mapTypeId: google.maps.MapTypeId.ROADMAP,
panControl: false,
streetViewControl: false,
mapTypeControl: false
};
jQuery(document).ready(function() {
On Friday, March 14, 2014 4:53:11 AM UTC-4, cyberoot wrote:
// Load google map
var map = new google.maps.Map(document.getElementById('gmap'), MapInfo);
var map1 = new google.maps.Map(document.getElementById('gmap1'), MapInfo );
}
One possible side effect of the above code is that the Map function might change the contents of the MapInfo object.
If that is undesirable, try this:
function MapInfoFun () {
return {
center: new google.maps.LatLng(0,0),
zoom: 3,
mapTypeId: google.maps.MapTypeId.ROADMAP,
panControl: false,
streetViewControl: false,
mapTypeControl: false
};
}
jQuery(document).ready(function() {
// Load google map
var map = new google.maps.Map(document.getElementById('gmap'), MapInfoFun());
var map1 = new google.maps.Map(document.getElementById('gmap1'), MapInfoFun() );
}
Can i Combine two id as one?I don't want to use two time document.getElementByID('gmap') and ('gmap1') Thanks you bro.jQuery(document).ready(function() { // Load google mapvar map = new google.maps.Map(document.getElementById('gmap'), { center: new google.maps.LatLng(0,0),zoom: 3,mapTypeId: google.maps.MapTypeId.ROADMAP,panControl: false,streetViewControl: false,mapTypeControl: false});var map1 = new google.maps.Map(document.getElementById('gmap1'), { center: new google.maps.LatLng(0,0),zoom: 3,mapTypeId: google.maps.MapTypeId.ROADMAP,panControl: false,streetViewControl: false,mapTypeControl: false});
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